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Question

​if the first term of an ap is -4 and the common difference is 2 then find the sum of its first 10 terms

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Solution

Let a be the first term and d be the common difference.Now, a = -4; d = 2Now, sum of first n terms of AP is given bySn = n22a + n-1dS10 = 1022-4 + 10-12=5-8 + 18=5 × 10=50

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