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Question

If the following compound is treated with $P d / C$ in excess of $H_{2}$ , what is the number of possible stereoisomers of product?

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Solution

The final product is symmetric compound,
Total numbers of stereoisomers for a symmetric compound = $(n)^{2}$
$n$ = No. of chiral centers
So Total stereoisomers = $2^{2} = 4$

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