Question

If the following orbital's are hybridized, then the hybridization will be respectively:

(i) One s orbital, two p orbitals (ii) One s orbital, three p orbitals (iii) One s orbital, one p orbital

• A. ${sp}^2$,${sp}^3$, $sp$
• B. $sp$, ${sp}^2$,${sp}^3$
• C. ${sp}^2$,${sp}^3$,${sp}^3$
• D. ${sp}^2$, $sp$, ${sp}^3$

Answer 1

The correct option is A

${sp}^2$,${sp}^3$, $sp$

Here, we have to keep in mind that the number of orbitals involved in hybridization will give the same number of hybrid orbitals.
For example:
If one s - orbital and one p - orbital is hybridizing, it will give two hybrid sp orbitals.
1s and 2p $\Rightarrow$ Three ${sp}^2$ hybrid orbitals
Now, we can see that
${sp}^2$ $\Rightarrow$ $s^1$$\to$ number of s - orbitals
$p^2$$\to$ number of p - orbitals

One s - orbitals, two p - orbitals

$\to$Three (${sp}^2$) hybrid orbitals

One s - orbital, three p - orbitals

$\to$Four (${sp}^3$) hybrid orbitals

One s - orbital, one p - orbital

$\to$Two $\left(sp\right)$ hybrid orbitals