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Question

If the force between two charged objects separated by a distance d is to be left unchanged even though the charge on one of the objects is halved, keeping other the same, the new distance of separation becomes :

A
d2
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B
d2
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C
2d
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D
2d
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Solution

The correct option is B d2

According to coulomb's inverse square law,

F=kq1q2d2

If charge on one of the objects is halved, but force remains unchanged,

F=kq12q2d12

Hence, q1d2=q12d12

d1=d2


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