Question

If the formula of chromic acid is $H_{2}Cr{O}_4$, then what is the formula of divalent metal chromate?

• A. $MCr{O}_4$
• B. $M_{2}Cr{O}_4$
• C. $M_2{\left(Cr{O}_4\right)}_3$
• D. $M_{3}Cr{O}_4$

Answer 1

The correct option is A $MCr{O}_4$

$H_{2}Cr{O}_4\Rightarrow 2H^{+}+Cr{O}_4^{2-}$

Hydrogen is mornovalent and cromate ion is

divalent ion.

$M^{2+}$ $Cr{O}_4^{2-}$ Simple Ratio $=1:1$

Valent $2$ $2$

10 Formula $=$ $MCr{O}_4$