Question

If the function f(x) defined by $f\left(x\right)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\cdots +\frac{x^2}{2}+x+1,then{f}^{\prime }\left(0\right)=$

• A. 100 f'
• B. 100
• C. 1
• D. -1

Answer 1

The correct option is C

1

$f^{\prime }\left(x\right)=x^{99}+x^{98}+x^{97}+\cdots \cdots \cdots \cdots \cdots +x+1$