If the function f (x) = x² - 8x + 12 satisfies the condition of Rolle's Theorem on (2, 6), find the value of c such that f '(c) = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
4

Suggest Corrections

Similar questions

c

[- 1, 3]

f (x) = x^{2} - 2 x - 8

f (x) = x (x + 3) e^{- (1 / 2) x}

f (x) = x^{3} + b x^{2} + a x + 5

[1, 3]

c = 2 + \frac{1}{\sqrt{3}}

a

b

f (x) = x (x + 3) e^{- (1 / 2) x}

[- 3, 0]

c

The value of c, for which the function $f (x) = x^{2} + 2 x - 8, x ϵ [- 4, 2]$ satisfies Rolle’s theorem, is

Join BYJU'S Learning Program