If the function g x is defined by g x - x 200-200- x 199-199- x 198-198- - - x 2-2- x -5- then g -0-A- 1B- 200C- 100D- 5

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Derivative from First Principle

If the functi...

Question

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1

g^’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.

Suggest Corrections

Similar questions

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

Q. If the function

g (x)

is defined by

g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + . . . . + \frac{x^{2}}{2} + x + 5

, then

g^{'} (0) =

_____

Q. If the function

g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5,

then

g^{'} (0) =

Q. If

f

and

g

are real functions defined by

f (x) = x^{2} + 7

and

g (x) = 3 x + 5

then

f (\frac{1}{2}) \times g (14)

If the function f(x) defined by $f (x) = \frac{x^{100}}{100} + \frac{x^{99}}{99} + \dots + \frac{x^{2}}{2} + x + 1, t h e n f^{'} (0) =$

Join BYJU'S Learning Program

If the function g(x) is defined by g(x)=x200200+x199199+x198198+……..+x22+x+5, then g′(0)=………….

The correct option is A 1 g’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

The correct option is A
1

g^’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.