If the function gx is defined by gx - x200-200-x199-199-x198-198-x2-2-x-5- then g-0-

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Question

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

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Solution

The correct option is A
1

g^’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.

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Similar questions

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

Q. If the function

g (x)

is defined by

g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + . . . . + \frac{x^{2}}{2} + x + 5

, then

g^{'} (0) =

_____

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

Q. If the function

g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots + \frac{x^{2}}{2} + x + 5,

then

g^{'} (0) =

Q. If

f

and

g

are real functions defined by

f (x) = x^{2} + 7

and

g (x) = 3 x + 5

then

f (\frac{1}{2}) \times g (14)

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If the function g(x) is defined by g(x)=x200200+x199199+x198198+……..+x22+x+5, then g′(0)=………….

The correct option is A 1 g’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.

If the function g(x) is defined by $g (x) = \frac{x^{200}}{200} + \frac{x^{199}}{199} + \frac{x^{198}}{198} + \dots \dots . . + \frac{x^{2}}{2} + x + 5,$ then $g^{'} (0) = \dots \dots \dots \dots .$

The correct option is A
1

g^’(0)= 1 as every term of g'(x) has x in each term except the last term which is 1.