If the HCF of x3−343andx2−9x+14is(x−7), then find their LCM
A
(x−7)(x−2)×(x2+7x+49)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(x−7)(x+2)×(x2+7x+49)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(x+7)(x−2)×(x2+7x+49)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A(x−7)(x−2)×(x2+7x+49) x3−343=x3−(7)3=(x−7)(x2+7x+49)x2−9x+14=x2−2x−7(x−2)=(x−7)(x−2) HCF of the polynomials (x−7)∴ Reqd. LCM==(x3−343)×(x2−9x+14)HCF=(x−7)(x2+7x+49)×(x−7)(x−2)(x−7)=(x−7)(x−2)×(x2+7x+49)