Question

If the heat of dissolution of $an.CuS{O}_4$ and $CuS{O}_4.5H_{2}O$ are (-15.89) kcal and 2.80 kcal respectively. Calculate the heat of hydration of $CuS{O}_4$:

• A. -13.09 kcal
• B. -18.69 kcal
• C. 13.09 kcal
• D. 18.69 kcal

Answer 1

The correct option is C 13.09 kcal

$CuS{O}_{4\left(s\right)}+aq\to CuS{O}_{4\left(aq\right)}\Delta H=15.89kcal\underset{–}{CuS{O}_4.5H_2{O}_{\left(s\right)}+aq\to CuS{O}_{4\left(aq\right)}\Delta H=2.80kcal}CuS{O}_{4\left(s\right)}+aq\to CuS{O}_4.5H_2{O}_{\left(aq\right)}\Delta H=?$
Subtracting equation 2 from equation 1 gives 13.09 kcal.