If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

Remain the same

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Be doubled

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Be quadrupled

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Be halved

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Solution

The correct option is C
Be quadrupled

$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2}$ . If initial velocity be doubled then maximum height reached by the projectile will quadrupled.

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If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

The correct option is C Be quadrupled H=u2 sin2 θ2g ∴ H∝u2. If initial velocity be doubled then maximum height reached by the projectile will quadrupled.

The correct option is C
Be quadrupled

$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2}$ . If initial velocity be doubled then maximum height reached by the projectile will quadrupled.