If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

Remain the same

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Be doubled

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Be quadrupled

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Be halved

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Be quadrupled

$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2}$ . If initial velocity be doubled then maximum height reached by the projectile will quadrupled.

Suggest Corrections

Similar questions

If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

Q. If the initial velocity of a projectile be doubled. Keeping the angle of projection same, the maximum height reached by it will

Q. A projectile fired with Initial velocity

u

at some angle

θ

has a range

R

. If the initial velocity be doubled at the same angle of' projection. then the range will be

A projectile fired with initial velocity u at some angle $θ$ has a range R. If the initial velocity be doubled at the same angle of projection, then the range will be

Q. A projectile is thrown with an initial velocity of

v = a^i + b^j

. If the range of projectile is doubled, then find the maximum height reached by it.

Join BYJU'S Learning Program

If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

The correct option is C Be quadrupled H=u2 sin2 θ2g ∴ H∝u2. If initial velocity be doubled then maximum height reached by the projectile will quadrupled.

The correct option is C
Be quadrupled

$H = \frac{u^{2} s i n^{2} θ}{2 g} ∴ H \propto u^{2}$ . If initial velocity be doubled then maximum height reached by the projectile will quadrupled.