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Question

If the interior angles of a pentagen measure x⁰, (x-10)⁰, (x+20)⁰, (2x-44)⁰ and (2x-70)⁰, then x = ___ .

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Solution

Sum of interior angles of a n sided polygon = (n - 2) x 180°

A pentagon has 5 sides.

Sum of interior angles of a pentagon = 3*180⁰ = 540⁰

(x + x - 10 + x + 20 + 2x - 44 + 2x - 70) = 540⁰

(7x - 104⁰) = 540⁰

7x = 644⁰

x = 92°


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