If the ionisation energy and electron affinity of an element are $275$ and $86$ $k c a l$ ${m o l}^{- 1}$ respectively, then the electronegativity of the element on the Mulliken scale is:

2.8

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Solution

The correct option is B $2.8$
According to Mulliken, electronegativity of an atom is average of ionization energy and electron affinity (in $e V$ ).
$n_{m} = \frac{I E + E A}{2}$
If ionisation energy and electron affinity are in $k c a l$ ${m o l}^{- 1}$ .
$n = \frac{I E + E A}{125} = \frac{275 + 86}{125} = 2.88$

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If the ionisation energy and electron affinity of an element are 275 and 86 kcal mol−1 respectively, then the electronegativity of the element on the Mulliken scale is:

The correct option is B 2.8According to Mulliken, electronegativity of an atom is average of ionization energy and electron affinity (in eV).nm=IE+EA2If ionisation energy and electron affinity are in kcal mol−1.n=IE+EA125=275+86125=2.88

If the ionisation energy and electron affinity of an element are $275$ and $86$ $k c a l$ ${m o l}^{- 1}$ respectively, then the electronegativity of the element on the Mulliken scale is: