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Question

If the ionization enthalpy and electron gain enthalpy of an element are 275 Kcal/mole and 86 Kcal mol1 respectively, then the electro negativity of the element on mulliken scale is


A

2.8

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B

0.0

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C

4.0

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D

2.6

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Solution

The correct option is A

2.8


E.N in Kcal/mole = I.E(KJ/mole+E.A(K.J/mole))540

I.E + E.A = 275 + 86 = 361 K Cal/mole.

=361 × 4.184 = 1510.42 KJ/mole

E.N = 1510.42540 = 2.797 2.8


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