Question

If the ionization enthalpy and electron gain enthalpy of an element are 275 Kcal/mole and 86 Kcal ${mol}^{-1}$ respectively, then the electro negativity of the element on mulliken scale is

• A. 2.8
• B. 0.0
• C. 4.0
• D. 2.6

Answer 1

The correct option is A

2.8

E.N in Kcal/mole = $\frac{I.E(KJ/mole+E.A(K.J/mole\left)\right)}{540}$

I.E + E.A = 275 + 86 = 361 K Cal/mole.

=361 $\times$ 4.184 = 1510.42 KJ/mole

E.N = $\frac{1510.42}{540}$ = 2.797 $\approx$ 2.8