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Molecular Speeds - Vrms, Vavg, Vmps

If the kineti...

Question

If the kinetic energy in $J$ , of $C H_{4}$ (Molar mass $= 16 g m o l^{- 1}$ ) at T(K) is X, the kinetic energy in $J$ , of $O_{2}$ (molar mass $= 32 g m o l^{- 1}$ ) at the same temperature is :

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X^{2}

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\frac{X}{2}

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Solution

The correct option is B X
At same temperature, Kinetic energy remains same
$K E_{1} = K E_{2} = X$
Option A is correct.

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Similar questions

J

C H_{4}

= 16 g m o l^{- 1})

T (K)

X

J

O_{2}

= 32 g m o l^{- 1})

O_{2}

32

0.048

N_{2}

28

O_{2}

32

0.048 e V

N_{2}

28

e V

O_{2}

N_{2}

C O R R E C T

C O

N_{2}

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