Question

The average translational kinetic energy of $O_2$(molar mass $32$) molecules at a particular temperature is $0.048$eV. The translational kinetic energy of $N_2$(molar mass $28$) molecules in eV at the same temperature is?

• A. $0.0015$
• B. $0.003$
• C. $0.048$
• D. $0.768$

Answer 1

The correct option is C $0.048$

Given: Molar mass of oxygen = 32

Molar mass of nitrogen= 28

Kinetic energy of oxygen molecules= 0.048 eV

Solution: The average translational energy for any gas is given by,

$E=\frac{3}{2}KT$

where, K is Boltzmann constant and T is the temperature.

From the above equation we conclude that energy is directly proportional to the temperature.

As, according to the question temperature is same for the nitrogen gas,

So the kinetic energy for nitrogen is also same as that of oxygen. i.e. $0.048eV$

Hence, the correct option is (C).