If the larger circle of radius 6 cm has four smaller circles of radius 2 cm, then find the area of the shaded portion.

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Solution

Given,
$R a d i u s o f t h e l a r g e r c i r c l e, r_{1} = 6 c m$
$a n d r a d i u s o f t h e s m a l l e r c i r c l e, r_{2} = 2 c m$

Area of shaded portion
$= π r_{1}^{2} - 4 π r_{2}^{2}$
$= π (6^{2} - 4 \times 2^{2}) = π (36 - 16) = 3.14 \times 20 = 62.8 c m^{2}$

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If the larger circle of radius 6 cm has four smaller circles of radius 2 cm, then find the area of the shaded portion.

Given, Radius of the larger circle, r1=6 cm and radius of the smaller circle, r2=2 cm Area of shaded portion =πr21−4πr22 =π(62−4×22)=π(36−16)=3.14×20=62.8 cm2

Given,
$R a d i u s o f t h e l a r g e r c i r c l e, r_{1} = 6 c m$
$a n d r a d i u s o f t h e s m a l l e r c i r c l e, r_{2} = 2 c m$

Area of shaded portion
$= π r_{1}^{2} - 4 π r_{2}^{2}$
$= π (6^{2} - 4 \times 2^{2}) = π (36 - 16) = 3.14 \times 20 = 62.8 c m^{2}$