Question

If the law of conservation of mass was to hold true, then $20.8\text{g}$ of $BaC{l}_2$ on reaction with $9.8\text{g}$ of $H_{2}S{O}_4$ will produce $7.3\text{gm}$ of $HCl$ and what mass of $BaS{O}_4$?

• A. $11.65\text{g}$
• B. $23.3\text{g}$
• C. $25.5\text{g}$
• D. $30.6\text{g}$

Answer 1

The correct option is B $23.3\text{g}$

The law of conservation of mass means mass remains same.
$\underset{20.8\text{g}}{BaC{l}_2}+\underset{9.8\text{g}}{H_{2}S{O}_4}\to \underset{x}{BaS{O}_4}+\underset{7.3\text{g}}{2HCl}$
if all reactants are consumed in reaction then $\Rightarrow$
Total mass of reactant = Total mass of product
$(20.8\text{g}+9.8\text{g})=(x+7.3\text{g})\Rightarrow 30.6-7.3=23.3\text{g}$
Mass of $BaS{O}_4=23.3\text{g}$