If the length and breadth of a rectangle are $(x^{2} - x + 2)$ cm and $(x^{2} + x - 2)$ cm respectively, find the area of the rectangle.

$(x^{4} - 5 x^{3} - x^{2}$ ) sq cm

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$(x^{4} - x^{3} - 4 x^{2} + 4$ ) sq cm

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$(x^{4} - x^{3} - x^{2} - 4 x$ ) sq cm

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$(x^{4} - x^{2} + 4 x - 4$ ) sq cm

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Solution

The correct option is D
$(x^{4} - x^{2} + 4 x - 4$ ) sq cm

Area of the rectangle = $l e n g t h \times b r e a d t h$

$(x^{2} - x + 2) \times (x^{2} + x - 2)$
$= x^{4} + x^{3} - 2 x^{2} - x^{3} - x^{2} + 2 x + 2 x^{2} + 2 x - 4$
= $x^{4} - x^{2} + 4 x - 4$ sq cm

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Similar questions

If the length and breadth of a rectangle are $(x^{2} - x + 2)$ cm and $(x^{2} + x - 2)$ cm respectively, find the area of the rectangle.

(x^{2} - x + 2)

(x^{2} + x - 2)

(x^{2} - x - 2)

(x^{2} + x - 2)

x^{4} - x^{2} + 4 x - 4

Area of a rectangle of length 10 cm and breadth 5.5 cm is

x^{2}

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