If the length and breadth of a room are $15 m$ and $10 m$ respectively, then
Breadth : Perimeter $=$ ________ $[1 : 5 / 1 : 15]$

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Solution

Given that,
Length of the room $= 15 m$
Breadth of the room $= 10 m$
Perimeter of the room $= 2 (15 + 10) = 50 m$
Now, ratio of breadth of the room to perimeter of the room $= 10 : 50$
Lowest form of $10 : 50 = \frac{10}{50} = \frac{1}{5} = 1 : 5$ ( Divide both $10$ and $50$ by their HCF $10$ )
Hence, Breadth : perimeter $=$ $1 : 5$

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