If the length of a rectangular plot is increased by 60%, by what percentage should its breadth be increased so that its area may increase by 75%?

9.37%

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11.75%

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13.67%

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15.55%

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Solution

The correct option is A 9.37%
Let the increase in the breadth be x%
$% increase in area = \frac{(100 + % increase in length) * (100 + % increase in breadth)}{100} - 100 75 = \frac{(100 + 60) * (100 + x)}{100} - 100 175 = \frac{160 * (100 + x)}{100} \frac{17500}{160} = 100 + x Thus, x = 9.375 %$

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Q. Q. If the length of a rectangular plot is increased by 60%, by what percentage should it’s breadth be increased so that its area may increase by 75%?

Q. यदि आयताकार भूखंड की लंबाई 60% तक बढ़ जाती है, तो इसकी चौड़ाई में कितने प्रतिशत की वृद्धि की जानी चाहिए ताकि इसका क्षेत्रफल 75% बढ़ जाये?

Q. If the length of a rectangular plot is increased by $60 %$ , by what percentage should it’s breadth be increased so that its area may increase by $75 %$ ?

Q. यदि एक आयताकार भूखंड की लंबाई में $60 %$ की वृद्धि की जाती है, तो इसकी चौड़ाई में कितने प्रतिशत की वृद्धि की जानी चाहिए ताकि इसके क्षेत्रफल में $75 %$ की वृद्धि हो सके?

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If the length of a rectangular plot is increased by 60%, by what percentage should its breadth be increased so that its area may increase by 75%?

The correct option is A 9.37%Let the increase in the breadth be x% % increase in area=(100 + %increase in length)*(100 + % increase in breadth)100 − 10075 = (100 + 60)*(100 + x)100 − 100175 = 160*(100 + x)10017500160 = 100 + xThus, x = 9.375%

The correct option is A 9.37%
Let the increase in the breadth be x%
$% increase in area = \frac{(100 + % increase in length) * (100 + % increase in breadth)}{100} - 100 75 = \frac{(100 + 60) * (100 + x)}{100} - 100 175 = \frac{160 * (100 + x)}{100} \frac{17500}{160} = 100 + x Thus, x = 9.375 %$