If the length of the parallel sides of a trapezium are $8 c m, 9 c m$ and the distance between the parallel sides is $6 c m$ , then its area is

51 c m^{2}

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68 c m^{2}

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34 c m^{2}

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72 c m^{2}

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Solution

The correct option is A $51 c m^{2}$
Length of parallel sides $= 8$ cm, $9$ cm
Distance between parallel sides $= 6$ cm
Area $= \frac{1}{2}$ (distance between parallel sides) $\times$ (sum of parallel sides)
$= \frac{1}{2} \times 6 \times (8 + 9) = 3 \times 17 = 51$

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If the length of the parallel sides of a trapezium are 8 cm,9 cm and the distance between the parallel sides is 6 cm, then its area is

The correct option is A 51 cm2Length of parallel sides=8 cm, 9 cmDistance between parallel sides=6 cmArea =12 (distance between parallel sides)× (sum of parallel sides)=12×6×(8+9)=3×17=51

If the length of the parallel sides of a trapezium are $8 c m, 9 c m$ and the distance between the parallel sides is $6 c m$ , then its area is

The correct option is A $51 c m^{2}$
Length of parallel sides $= 8$ cm, $9$ cm
Distance between parallel sides $= 6$ cm
Area $= \frac{1}{2}$ (distance between parallel sides) $\times$ (sum of parallel sides)
$= \frac{1}{2} \times 6 \times (8 + 9) = 3 \times 17 = 51$