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Question

If the line
xx1a1=yy1b1=zz1c1
makes an angle θ with the plane a2x+b2y+c2z=d, then which of the following is correct -

A
cos(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
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B
sin(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
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C
tan(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
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D
cot(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
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Solution

The correct option is B sin(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
We know in the given equation of line a1,b1,c1 are the direction ratios of the line and in the equation of plane a2,b2,c2 are the direction ratios of the normal to the plane. So we have two vectors with us. All we need now is the angle between them.
If the angle between plane and line is θ, then the angle between normal to the plane and line is 90θ.
cos(90θ)=a.b|a||b|
cos(90θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)

sin(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)

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