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Question

If the lines 3x+2ky=2 and 2x+5y+1=0 are parallel, then find the value of k.

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Solution

Suppose that we have to parallel lines a1x+b1y+c1=0 & a2x+b2y+c2=0 then,ratio of coefficient of x and y are equal i.e. a1a2=b1b2.
Now, according to given equations
3x+2ky=2
2x+5y+1=0
compairing coeffient of x& y and applying rule,
32=2k5
4k=15
So value of k=154.

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