If the lines 3x - 4y + 4 = 0 and 6x - 8y - 7 = 0 are tangents to a circle, then the radius of the circle is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
The diameter of the circle is perpendicular distance between the parallel lines (tangents) 3x - 4y + 4 = 0 and 3x - 4y + 4 = 0 and $3 x - 4 y - \frac{7}{2} = 0$ and so it is equal to $\frac{4}{\sqrt{9 + 16}} + \frac{7 / 2}{\sqrt{9 + 16}} = \frac{3}{2}$ .
Hence radius is $\frac{3}{4}$ .

Suggest Corrections

Similar questions

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

If the lines $3 x - 4 y + 4 = 0$ amd $6 x - 8 y - 7 = 0$ are tangents to a circle, find the radius of the circle.

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

3 x - 4 y = 4

6 x - 8 y - 7 = 0

Join BYJU'S Learning Program