If the lines 3x - 4y + 4 = 0 and 6x - 8y - 7 = 0 are tangents to a circle, then the radius of the circle is

3/2

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3/4

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1/10

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1/20

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Solution

The correct option is B 3/4
The diameter of the circle is perpendicular distance between the parallel lines (tangents) 3x - 4y + 4 = 0 and $3 x - 4 y - \frac{7}{2} = 0$ and so it is equal to $\frac{4}{\sqrt{9 + 16}} + \frac{7 / 2}{\sqrt{9 + 16}} \frac{3}{2} .$ Hence radius is \frac{3}{4}.

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Similar questions

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

If the lines $3 x - 4 y + 4 = 0$ amd $6 x - 8 y - 7 = 0$ are tangents to a circle, find the radius of the circle.

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

3 x - 4 y = 4

6 x - 8 y - 7 = 0

3 x + 4 y - 14 = 0

6 x + 8 y + 7 = 0

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