Question

If the lines are drawn in proportion to the charge, what is the ratio $\frac{q_1}{q_2}$?

• A. 1/3
• B. 3
• C. 1/6
• D. cannot be said

Answer 1

The correct option is A

1/3

since, the relative number of EFL originating from or terminating on a charge is proportional to the magnitude of the charge. This ratio of their charges $\frac{q_1}{q_2}$ must be equal to the ratio of number of electric field lines emanating from $q_{1}and{q}_2.$

By carefully while observing the picture,$\frac{q_1}{q_2}=\frac{6}{16}=\frac{3}{8}$