If the lines given by ax2 +2hxy + by2 =0from an equilateral triangle with the lines Lx+my =1then show that (3a+b)(a+3b)-4h2=0

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If the pair of straight lines given by $A x^{2} + 2 H x y + B y^{2} = 0, (H^{2} > A B)$ forms an equilateral triangle with line ax + by + c = 0, then (A + 3B)(3A + B) is

Q. Show that the area of the triangle formed by the lines

a x^{2} + 2 h x y + b y^{2} = 0

and

l x + m y + n = 0

\frac{n^{2} \sqrt{h^{2} - a b}}{∣ ∣ a m^{2} - 2 h l m + b l^{2} ∣ ∣}

Q. Find the area of the triangle formed by the lines

a x^{2} + 2 h x y + b y^{2}

and

l x + m y + n = 0

Q. If the pair of straight lines given by

A x^{2} + 2 H x y + B y^{2} = 0 (H^{2} > A B)

forms an equilateral triangle with line

a x + b y + c = 0

, then

(A + 3 B) (3 A + B) =

If (a + 3b)(3a + b) = $4 h^{2}$ , then the angle between the lines represented by $a x^{2} + 2 h x y + b y^{2} = 0$ is

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If the lines given by ax2 +2hxy + by2 =0from an equilateral triangle with the lines Lx+my =1then show that (3a+b)(a+3b)-4h2=0

We found a similar question to the one that you posted. Please check it out here. similiar question. Like if satisfied

We found a similar question to the one that you posted. Please check it out here.

similiar question.

Like if satisfied