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Question

If  the lines (p+1)x+y=3 and 3y(p1)x=4 are perpendicular to each other, find p.


A

1

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B

2

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C

-1

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D

-2

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Solution

The correct options are
B

2


D

-2


When we convert the given lines into y=mx+c   form ,we get

y=(p+1)x+3 and y=(p1)3x+43
Here m1=(p+1) and m2=(p1)3
Lines are perpendicular to each other
 m1m2=1
(p+1)(p1)3=1
p21=3

 p2=4
 
p=±2


Mathematics

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