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KE & PE Graph

If the maximu...

Question

If the maximum velocity of a particle in SHM is $v_{0}$ , then its velocity at half the amplitude from position of rest will be :

v_{0} / 2

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v_{0}

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v_{o} \sqrt{3} / 2

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v_{0} \sqrt{4} / 2

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Solution

The correct option is C $v_{o} \sqrt{3} / 2$
Hence, the option $C$ is the correct answer.

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The velocity of a particle is V=V0+gt+ft if its position is X=0 at t=0 then it's displacement after unit time t=1 is

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