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Question

If the median of the following data is 32.5, find the missing frequencies.
Class interval:010102020303040405050606070Total
Frequency:f15912f23240

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Solution

Class intervalFrequency Cumulative frequency
010f1f1
10205 5+f1
20309 14+f1
304012 26+f1
4050f2 26+f1+f2
50603 29+f1+f2
60702 31+f1+f2
N=40
Median=32.5, then 3040 is class interval.

l=30,cf=14+f1,f=12 and h=4030=10.

N=40,N2=20

31+f1+f2=40.

Then, f1+f2=9 ----- ( 1 )

Median=l+N2cff×h

32.5=30+20(14+f1)12×10

2.5=6f16×5

15=305f1

5f1=15

f1=3

Substituting value in equation ( 1 ) we get,

3+f2=9

f2=6

f1=3,f2=6

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