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Standard XII

Chemistry

Derivation of Kp and Kc

If the molar ...

Question

If the molar concentrations at equilibrium of $X, Y$ and $Z$ are $2 M, 2 M$ and $4 M$ respectively, then the equilibrium constant for the reaction $X + 3 Y ⇋ 2 Z$ is:

1

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0.25

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Solution

The correct option is A $1$
The equilibrium reaction is as follows:

$X + 3 Y ⇋ 2 Z$
The expression for the equilibrium constant, $K_{c} = \frac{[Z]^{2}}{[X] [Y]^{3}}$
Substituting values in the above expression, we get
$K_{c} = \frac{4^{2}}{2 \times 2^{3}} = 1$

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If the molar concentrations at equilibrium of X, Y and Z are 2 M,2 M and 4 M respectively, then the equilibrium constant for the reaction X+3Y⇋2Z is:

The correct option is A 1The equilibrium reaction is as follows:X+3Y⇋2ZThe expression for the equilibrium constant, Kc=[Z]2[X][Y]3Substituting values in the above expression, we getKc=422×23=1

If the molar concentrations at equilibrium of $X, Y$ and $Z$ are $2 M, 2 M$ and $4 M$ respectively, then the equilibrium constant for the reaction $X + 3 Y ⇋ 2 Z$ is:

The correct option is A $1$
The equilibrium reaction is as follows:

$X + 3 Y ⇋ 2 Z$
The expression for the equilibrium constant, $K_{c} = \frac{[Z]^{2}}{[X] [Y]^{3}}$
Substituting values in the above expression, we get
$K_{c} = \frac{4^{2}}{2 \times 2^{3}} = 1$