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Molarity

If the molari...

Question

If the molarity of $200 m l$ solution of glucose $(C_{6} H_{12} O_{6})$ is $0.2$ , then the mass of glucose present in the solution is:

18 g

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7.2 g

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12.4 g

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36.2 g

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Solution

The correct option is A $18 g$
Given molarity of the solution $= 0.2$

Volume of solution $= 200 m l = 0.2$ L

$M o l a r i t y = \frac{M o l e s o f s o l u t e}{V o l u m e i n l i t r e s}$

Moles of solute $= 0.2 \times 0.2 = 0.04$

$N o . o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s}$

Molar mass of $C_{6} H_{12} O_{6}$ = $6 \times 12 + 12 + 6 \times 16 = 180$ g

Mass of glucose in the solution = $180 \times 0.04 = 7.2$ g

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