Question

If the multiplicative inverse of a complex number is $(\sqrt{3}+4i)(wherei=\sqrt{-1)}$ then the complex number itself is

• A. $\sqrt{3}-4i$
• B. $4+i\sqrt{3}$
• C. $\sqrt{3}+4i$
• D. $4-i\sqrt{3}$

Answer 1

The correct option is A $\sqrt{3}-4i$

Given,

Inverse of a complex number $=\sqrt{3}+4i$

we have, if a complex number is $a+ib$

then its complex number is given by, $a-ib$

Therefore complex number of given inverse is,

$=\sqrt{3}-4i$