You visited us 2 times! Enjoying our articles? Unlock Full Access!

If the normal...

Question

If the normal to the rectangular hyperbola $x y = c^{2}$ at the point $(t_{1})$ meets the curve again at the point $(t_{2})$ , then

t_{1}^{3} t_{2} = - 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

t_{1}^{3} t_{2} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

t_{1} t_{2}^{3} = - 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $t_{1}^{3} t_{2} = - 1$
If the normal to the rectangular hyperbola $x y = c^{2}$ at the point $(t_{1})$ meets the curve again at the point $(t_{2})$ , then $t_{1}^{3} t_{2} = - 1$

Suggest Corrections

Similar questions

Q. If normal to the rectangular hyperbola

x y = 4

at the point

t_{1} (= 4)

meets the curve again at the point

t_{2}

, then

\frac{1}{| t_{2} |} =

The normal to the rectangular hyperbola $x y = c^{2}$ at the point ' $t_{1}$ ' meets the curve again at the point ' $t_{2}$ '. Then the value of $t_{1}^{3} t_{2}$ is

Q. The normal to the rectangular hyperbola

x y = - c^{2}

at the point

^{'} t_{1}^{'}

meets the curve again at the point

^{'} t_{2}^{'}

. The value of

t_{1}^{3} \cdot t_{2}

Q. If normal to the rectangular hyperbola

x y = 4

at the point

t_{1} (= 4)

meets the curve again at the point

t_{2}

, then

\frac{1}{| t_{2} |} =

Q. If the normal at the point

^{'} t_{1}^{'}

to the rectangular hyperbola

x y = c^{2}

meets it again at the point

^{'} t_{2}^{'}

then the value of

t_{1} t_{2}

is:

Join BYJU'S Learning Program

If the normal to the rectangular hyperbola xy=c2 at the point (t1) meets the curve again at the point (t2), then

The correct option is A t31t2=−1If the normal to the rectangular hyperbola xy=c2 at the point (t1) meets the curve again at the point (t2), then t31t2=−1

If the normal to the rectangular hyperbola $x y = c^{2}$ at the point $(t_{1})$ meets the curve again at the point $(t_{2})$ , then

The correct option is A $t_{1}^{3} t_{2} = - 1$
If the normal to the rectangular hyperbola $x y = c^{2}$ at the point $(t_{1})$ meets the curve again at the point $(t_{2})$ , then $t_{1}^{3} t_{2} = - 1$