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Question

If the nth term of an AP is (3n + 5), then its common difference is
(a) 5
(b) 4
(c) 3
(d) 2

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Solution

(c) 3
Here, Tn = 3n + 5
Then, T1 = 3 ⨯ ​1 + 5 = 8
Also, T2 = 3 ⨯ ​2 + 5 = 11​
∴ d = T2 - T1 = 11 - 8 = 3

Hence, the common difference is 3.


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