Question

If the numbers $a,b,c,d,e$, form an A.P , then the value of $a-4b+6c-4d+e$ is-

• A. $1$
• B. $2$
• C. $0$
• D. None of these

Answer 1

The correct option is C $0$

$a,b,c,d,e$ are in A.P

$\therefore b=a+D$

$c=a+2D$

$d=a+3D$

$e=a+4D$

Here D is the common difference substitute the values of b,c,d and e in the given expression.

$a-4b+6c-4d+e$

$=a-4(a+D)+6(a+2D)-4(a+3D)+a+4D$

$=a-4a-4D+6a+12D-4a-12D+a+4D$

$=8a-8a$

$=0$