Question

If the observed and theoretical molecular mass of NaCl is found to be 31.80 and 58.50, then the degree of dissociation of NaCl is:

• A. 83.96%
• B. 8.39%
• C. 90%
• D. 100%

Answer 1

The correct option is A 83.96%

$i=\frac{58.50}{30.80}=1.8396$

$\alpha =\frac{i-1}{m-1}=\frac{1.8396-1}{2-1}$

$=0.8396$ or $83.96$ %

Hence, the correct option is $A$