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Multi-Electron Configurations and Orbital Diagrams

If the observ...

Question

If the observed dipole moment of HF is 1.944 D and the bond length of HF is 90 pm. Find the $%$ covalent character of HF.

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Solution

$Percentage ionic character = \frac{o b s e r v e d d i p o l e m o m e n t (i n D)}{4.8 \times bond length (i n \circ A)} \times 100 = \frac{1.944}{4.8 \times 0.9} \times 100 = 45 %$

Therefore, the $%$ covalent character = $55 %$

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