If the odd in favour of an event are $4$ to $7$ , find the probability of its no occurence.

\frac{9}{11}

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\frac{7}{11}

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\frac{4}{11}

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\frac{3}{11}

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Solution

The correct option is C $\frac{7}{11}$
The odds in favour of the event is $4 : 7$
Favourable elements for event $A$ is $4 x$
Unfavourable elements for event $A$ is $7 x$
Therefore, the probability that an event does not occurs
$= \frac{7 x}{4 x + 7 x} = \frac{7}{11}$

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(ii) The odds against its occurrence.

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(i) $\frac{- 15}{8} \times \frac{- 12}{7} = \frac{- 12}{7} \times \frac{- 15}{8}$

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(iii) $\frac{- 3}{4} \times (\frac{- 3}{4} \times \frac{- 5}{6}) + (\frac{- 3}{4} \times \frac{7}{8})$

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(vi) $\frac{- 7}{5} \times 0 = 0$

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