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Question

If the ordinate is twice the abscissa, then find the point where
7x3y=8.


A

(8,16)

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B

(2,4)

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C

(3,6)

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D

(6,3)

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Solution

The correct option is A

(8,16)


Let, the abscissa x = k and the ordinate y = 2k.

Substituting the value in the given equation:

7x3y=8.

7(k)3(2k)=8

k=8

Thus, Abscissa x = k = 8 and ordinate y = 2k = 16.

Thus, the given point is (8,16).


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