If the picnic site is 55 km from school and the first stop is at a place 22 km from school, what is the percentage of the remaining distance in this?

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Solution

The correct option is D 60
Remaining distance = 55 - 22 = 33. Hence, the percentage of 33 out of 55 is to be found out.
Percentage of 33 out of $55 = \frac{33}{55} \times 100 = \frac{3}{5} \times 100 = 60 %$

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Q. The picnic spot is 55 km away. The first stop is taken at 22 km from the school. percentage of the distance is remaining to reach the destination.

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If the picnic site is 55 km from school and the first stop is at a place 22 km from school, what is the percentage of the remaining distance in this?

The correct option is D 60Remaining distance = 55 - 22 = 33. Hence, the percentage of 33 out of 55 is to be found out. Percentage of 33 out of 55=3355×100=35×100=60%

The correct option is D 60
Remaining distance = 55 - 22 = 33. Hence, the percentage of 33 out of 55 is to be found out.
Percentage of 33 out of $55 = \frac{33}{55} \times 100 = \frac{3}{5} \times 100 = 60 %$