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Question

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.


A

k=157

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B

k=137

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C

k=157

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D

k=137

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Solution

The correct option is A

k=157


Since the point (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0,

2(2k3)+3(k+2)+15=0

4k6+3k+6+15=0

7k=15k=157


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