Question

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.

• A. $k=\frac{-15}{7}$
• B. $k=\frac{-13}{7}$
• C. $k=\frac{15}{7}$
• D. $k=\frac{13}{7}$

Answer 1

The correct option is A $k=\frac{-15}{7}$

Since the point (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0,

$2(2k-3)+3(k+2)+15=0$

$\Rightarrow 4k-6+3k+6+15=0$

$\Rightarrow 7k=-15\Rightarrow k=\frac{-15}{7}$