If the point (5, 2) bisects the intercept of a line between the axes, then its equation is
2 x+5 y=20
Let the equation of the line be xa+yb=1
The coordinates of the intersection of this line with the coordinate axes are (a, 0) and (0, b)
The midpoint of (a, 0) and (0, b) is
(a2,b2)
According to the question :
(a2,b2)=(5,2)
⇒ a2=5,b2=2
⇒ a=10, b=4
The equation of the required line is given below :
x10+y4=1
⇒ 2x+5y=20