If the point P(a,1) lies on the line 2x-3y-5=0, then find the value of a.

-4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
4

If a point (a, 1) lies on the line 2x-3y-5=0, then the point should satisfy the line.
$2 x - 3 y - 5 = 0 \to 2 \times a - 3 \times 1 - 5 = 0 \to 2 a - 8 = 0 \to 2 a = 8 \to a = 4$

Suggest Corrections

Similar questions

If the point P(3,a) lies on the line x + 2y = 3, then find the value of a.

If the point P(8, a) lies on the line $\frac{x}{4} + \frac{y}{5} = 1$ , then find the value of a.

(x_{1}, 4), (- 2, y_{1})

(2, - 1)

(5, - 3)

P (x_{1}, y_{1})

Join BYJU'S Learning Program