Question

If the points (2k-3,k+2) lie on the graph of the equation 2x+3y+15=0, find the value of k.

Answer 1

x=2k-3, y=k+2 (given)
eq.=2x+3y+15=0.
therefore,
2(2k-3)+3(k+2)+15=0
4k-6+3k+6=-15
4k+3k-6+6=-15
7k-0=-15
7k=-15
k=-15/7